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| Tweet Topic Started: Aug 30 2009, 06:25 PM (1,055 Views) | |
| chagi | Sep 14 2009, 11:01 AM Post #31 |
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Metroid
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yes it is |
| doobie doo | |
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| Timmeh | Sep 14 2009, 10:42 PM Post #32 |
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The Electryc Penys
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Again, you cannot state a length in terms of i. That will be all. Chagi, nein. x^2 = 25 isn't the same as solving for the side of a square (x) with an area of 25. The answers are, respectively: 1) x = +/- 5 2) x = 5 And there's a reason for that. There exists no such thing as a negative length (or imaginary length). |
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| Pomegranate | Sep 15 2009, 01:39 AM Post #33 |
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Prime Essence
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but... i just did... |
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| chagi | Sep 15 2009, 07:34 AM Post #34 |
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Metroid
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Oh hey, the solutions are x = 5 and an hypothetical x = -5 I'll just let that word sink in for you; hypothetical read it a few times and you will soon realise that its true |
| doobie doo | |
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| Timmeh | Sep 15 2009, 08:27 AM Post #35 |
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The Electryc Penys
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It's actually a logical proven -5. Addition and multiplication are defined such that -5 * -5 = 25. It's not any more hypothetical than the positive 5. There is no way to derive the length of a square with an area of 200i from first principles. Anyway, I just spent a while doing this question for math homework, have a ball with it: I hope the images for the equations stay up. If not, they're x^2 + y^2 + z^2 = 4 and x^2 + y^2 + z^2 + 4x - 2y + 4z + 5 = 0 Pom, I should have said you can't say a length in the form of a complex number (a + bi) where b can't simplify to 0. Better? |
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| Pomegranate | Sep 16 2009, 11:27 PM Post #36 |
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Prime Essence
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yes. |
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| Liksmaskaren | Sep 16 2009, 11:33 PM Post #37 |
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The Swede
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You are nerds. |
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| Pomegranate | Sep 17 2009, 01:14 AM Post #38 |
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Prime Essence
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quiet you! |
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| Liksmaskaren | Sep 17 2009, 06:41 PM Post #39 |
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The Swede
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No. This topic scares me! I feel so fucking dumb! |
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| DeProgrammer | Sep 17 2009, 07:28 PM Post #40 |
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Elite Pirate
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We are the epitome of nerd. Its quintessence, even! Bow before us, knave! ... *pat pat* |
![]() Signature by Rewrite. My talent comes from deep within...like vomit! | |
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| chagi | Sep 18 2009, 07:30 PM Post #41 |
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Metroid
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Wait, what are you saying now? That length can be negative, or that it can't? Oh, and that shit with the spheres... blargh |
| doobie doo | |
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| Liksmaskaren | Sep 18 2009, 08:26 PM Post #42 |
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The Swede
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Nerds are scary. |
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| Phlakes | Oct 4 2009, 01:58 PM Post #43 |
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Omega Pirate
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Two ridiculously easy proofs. Given: 13x-2y=3 25x-11y=1 Prove: The solution to the system of equations is (1/3, 2/3) AND
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| Timmeh | Oct 4 2009, 07:24 PM Post #44 |
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The Electryc Penys
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Did you have to choose to make a system with a bunch of fucking prime numbers? ![]() The proof is just plugging them in though. 13/3 - 4/3 = 3 -> 13 - 4 = 9 25/3 - 22/3 = 1 -> 25 - 22 = 3 The line one... Assume they're parallel. If they are, <EXY = <XYF, so we need to show that. <AXD = <BXE <AXD + <DXE = pi <BXE + <BXA = pi <DXE = <BXA <BXA = <EXY, I forget why, but they're opposite angles in intersecting lines. <XYF = <DXE = <BAX = <EXY <XYF = <EXY, QED |
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| s123i68 | Oct 4 2009, 09:38 PM Post #45 |
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Omega Pirate
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Geeze...that's...a little disconcerting. Uh...I can derive things...that's kinda cool, I guess... But what you guys are doing confuses the crap out of me. That's what I get for being too lazy to read the first 3 pages.
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